2x[x+(2x-3)]=5x-(3x+2)

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Solution for 2x[x+(2x-3)]=5x-(3x+2) equation:


Simplifying
2x[x + (2x + -3)] = 5x + -1(3x + 2)

Reorder the terms:
2x[x + (-3 + 2x)] = 5x + -1(3x + 2)

Remove parenthesis around (-3 + 2x)
2x[x + -3 + 2x] = 5x + -1(3x + 2)

Reorder the terms:
2x[-3 + x + 2x] = 5x + -1(3x + 2)

Combine like terms: x + 2x = 3x
2x[-3 + 3x] = 5x + -1(3x + 2)
[-3 * 2x + 3x * 2x] = 5x + -1(3x + 2)
[-6x + 6x2] = 5x + -1(3x + 2)

Reorder the terms:
-6x + 6x2 = 5x + -1(2 + 3x)
-6x + 6x2 = 5x + (2 * -1 + 3x * -1)
-6x + 6x2 = 5x + (-2 + -3x)

Reorder the terms:
-6x + 6x2 = -2 + 5x + -3x

Combine like terms: 5x + -3x = 2x
-6x + 6x2 = -2 + 2x

Solving
-6x + 6x2 = -2 + 2x

Solving for variable 'x'.

Reorder the terms:
2 + -6x + -2x + 6x2 = -2 + 2x + 2 + -2x

Combine like terms: -6x + -2x = -8x
2 + -8x + 6x2 = -2 + 2x + 2 + -2x

Reorder the terms:
2 + -8x + 6x2 = -2 + 2 + 2x + -2x

Combine like terms: -2 + 2 = 0
2 + -8x + 6x2 = 0 + 2x + -2x
2 + -8x + 6x2 = 2x + -2x

Combine like terms: 2x + -2x = 0
2 + -8x + 6x2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(1 + -4x + 3x2) = 0

Factor a trinomial.
2((1 + -3x)(1 + -1x)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(1 + -3x)' equal to zero and attempt to solve: Simplifying 1 + -3x = 0 Solving 1 + -3x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -3x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -3x = 0 + -1 -3x = 0 + -1 Combine like terms: 0 + -1 = -1 -3x = -1 Divide each side by '-3'. x = 0.3333333333 Simplifying x = 0.3333333333

Subproblem 2

Set the factor '(1 + -1x)' equal to zero and attempt to solve: Simplifying 1 + -1x = 0 Solving 1 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1x = 0 + -1 -1x = 0 + -1 Combine like terms: 0 + -1 = -1 -1x = -1 Divide each side by '-1'. x = 1 Simplifying x = 1

Solution

x = {0.3333333333, 1}

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